A ball is dropped from the top of the building. The ball falls3 times farther du

Question

A ball is dropped from the top of the building. The ball falls3 times farther during its last second in freefall than its thirdsecond of freefall. If the ball fell 4.9 meters during its firstsecond, how tall is the building and how long was the ball in theair? answer= (change in) y= 313.6 m A ball is dropped from the top of the building. The ball falls3 times farther during its last second in freefall than its thirdsecond of freefall. If the ball fell 4.9 meters during its firstsecond, how tall is the building and how long was the ball in theair? answer= (change in) y= 313.6 m

Explanation / Answer

    Initial velocity, U = 0     Distance traveled in 1 st second, S1 = U + a ( n- 1/2 )                                                      - 4.9 = 0 + a ( 1 - 1/2 )                                                            a = - 9.8 m/s^2     Distance traveled in 3rd second, S3 = U + a ( n- 1/2 )                                                           = 0 - 9.8 ( 3 - 1/2 )                                                           = - 24.5 m     Distance traveled in last second , Sn = U + g (n - 1/2 )                                                    3 * S3 = 0 - 9.8 ( n - 1/2 )                                                    3 * - 24.5 = - 9.8 ( n - 1/2 )                                                             By solving, time of travel, n = 8 s     Distance traveled during the fall , S = Ut+ ( 1/2 ) a t2                                                      = 0 - 4.9 * 82                                                      = - 313.6 m ( here '-' indicate downward direction )     Height of the building , h = 313.6 m

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