The plates of a spherical capacitor have radii of 8.70 cm and 9.00 cm. (a)Calcul

Question

The plates of a spherical capacitor have radii of 8.70 cm and 9.00 cm.

(a)Calculate thecapacitance.         I used c = 4(pi)(Eo)(((a*b)/(b-a)) No problem here

(b)What must be the plate area of a parallel plate capacitor withthe same plate separation and capacitance?    Justused my capacitance from above and used C = (Eo)(A)/d to findarea think its good here

(c)If there is a 5.0V potential differenceapplied to the above plates calculate the electric field betweenthe plates.     I believe its just V/d which would be 5/(.09-.087) not 100% sure.

(d) What is the surface charge density?
(e) Find the charge on each plate.
(f) What would be the surface charge density for the insidesphere?

as for these last 3 im not sure i beileve they just follow aformula nothing to serious, i would appriciate any help on d e andf. Thank you

Explanation / Answer

I'm guessing the method to C was correct? Is the Area in F justA=4(pi)r^2 for the inner radius?

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