mu 0 = 4 pi times 10 - 7 T m/s, e = 1.6 times 10 - 19 C, mp = 1.67 times 10 - 27

Question

mu 0 = 4 pi times 10 - 7 T m/s, e = 1.6 times 10 - 19 C, mp = 1.67 times 10 - 27 kg A proton, P + , with velocity V rightarrow = (3.0 times 105i + 4.0 times 105j) m/s is located at R rightarrow = 2.0i + 1.0j cm at t = 0 A long, straight wire on the x axis carries a current of 15 amps in the - x direction as shown in the figure. What is the magnetic field B rightarrow from the current at the position of the proton? What is the force F rightarrow P acting on the proton due to the magnetic field of the current? What is the speed of the proton at a time t = 2 times 10 - 8 seconds after it is in the position shown in the figure?

Explanation / Answer

A) magnitude B = 0I/(2y) =2.0*10-4 T direction: -z (using right hand rule) B) F = ev x B (cross porduct) = -eBvy i +eBvx j C) magnetic force does no work, speed is a constant =(vx2 + vy2) =5*105 m/s

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