I am having some trouble with this problem on my physics homework.Please help. I

Question

I am having some trouble with this problem on my physics homework.Please help. It is from physics (8th) Cutnell, Chapter 11, Problem70. It reads as follows:
Thanks

-A hand-pumped water gun is held level at a height of 0.79 m abovethe ground and fired. The water stream from the gun hits the grounda horizontal distance of 7.9 m from the muzzle. Find the gaugepressure of the water gun's reservoir at the instant when the gunis fired. Assume that the speed of the water in the reservoir iszero, and that the water flow is steady. Ignore both air resistanceand the height difference between the reservoir and the muzzle.

Explanation / Answer

      Given that the height differenceis h = 0.79 m       Horizontal distance covered by thewater is R = 7.9 m ---------------------------------------------------------------------     Let u is the velocity of fluid at bottom Horizontal distance covered is R = velocity * time offlight                                                    = v * (2h/g )                                                 v = R*(g/2h)                                                    = ---------- m/s Apply Bernoulli's equation          P1 +(1/2)u2 + gh1 = P2 +(1/2)v2 + gh2    P1 - P2   =  (1/2)v2 + g(h2 -h1) -(1/2)u2                               = (1/2)v2 + gh                        = --------- Pa

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