A 0.95 kg box is attached to a horizontalspring whose spring constant is 60 N/m.

Question

A 0.95 kg box is attached to a horizontalspring whose spring constant is 60 N/m.The coefficient of static friction between the box and the table onwhich it rests is s = 0.80.


(d) What is the algebraic expression for the maximum distancex that the spring can be stretched from its unstrainedposition without the box moving? e) What is the algebraic expression for the magnitudeFN of the normal force exerted on the box bythe table? f) Using the results of parts (a) and (b), calculate themaximum distance x that the spring can be stretched fromits unstrained position without the box moving
(d) What is the algebraic expression for the maximum distancex that the spring can be stretched from its unstrainedposition without the box moving? e) What is the algebraic expression for the magnitudeFN of the normal force exerted on the box bythe table? f) Using the results of parts (a) and (b), calculate themaximum distance x that the spring can be stretched fromits unstrained position without the box moving

Explanation / Answer

d) The maximum distance is where the force of the spring is equalto the force of friction. Fs=Ff => 60*x =.95kg*9.8m/s2*.80 => x = m*g*s/k => x=.1241m e) Fn=m*g=.95*9.8 f)distance is given in part d.

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