A student sits on a rotating stool holding two 3.0 kg objects. When his arms are
ID: 1723525 • Letter: A
Question
A student sits on a rotating stool holding two 3.0 kg objects. When his arms are extendedhorizontally, the objects are 1.0 m from the axis of rotation, andhe rotates with an angular speed of 0.75 rad/s. The moment ofinertia of the student plus stool is 3.0 kg·m2and is assumed to be constant. The student then pulls the objectshorizontally to 0.20 m from the rotationaxis.(a) Find the new angular speed of the student.1 rad/s
(b) Find the kinetic energy of the student before and after theobjects are pulled in. before 2 J after 3 J before 2 J after 3 J
Explanation / Answer
The moment of inertia of the student plus stool I = 3.0 kg·m2 mass m = 3 kg distance r = 1 m Initial total moment of inertia I ' = I + m r ^ 2 = 3 + ( 3 * 1 ^ 2 ) = 6 kg m ^ 2 Angular speed w ' = 0.75 rad / s New moment of inertia I " = I + m r ' ^ 2 = 3 + ( 3 * 0.2 ^ 2 ) =3 + 0.12 = 3.12 kg m ^ 2 (a). from law of conservation of angular momentum I ' w' = I " w " new angular speed w " = I ' w ' / I " = 1.442 rad / s (b). the kinetic energy of the student before the objectsare pulled in = ( 1/ 2) I ' w ' ^ 2 = 1.6875 J the kinetic energy of the student after the objects arepulled in = ( 1/ 2) I " w " ^ 2 =3.243 JRelated Questions
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