Part A On which of the following will a simplependulum that is 8.17 m long have

Question

Part A On which of the following will a simplependulum that is 8.17 m long have thegreatest frequency?

1 Venus (g = 8.87m/s2)
Earth (g = 9.78m/s2)    
Moon (g = 1.62m/s2)
Mars (g = 3.69m/s2)
Mercury (g = 3.70m/s2)

Part B On Earth, which ofthe following simple pendulums will have thesmallest frequency?

2 A pendulum 2.74m long.
A pendulum 2.99m long.    
A pendulum 2.27m long.
A pendulum 2.01m long.
A pendulum 2.15m long.

Got it wrong the first two times
1 Venus (g = 8.87m/s2)
Earth (g = 9.78m/s2)    
Moon (g = 1.62m/s2)
Mars (g = 3.69m/s2)
Mercury (g = 3.70m/s2)
1 Venus (g = 8.87m/s2)
Earth (g = 9.78m/s2)    
Moon (g = 1.62m/s2)
Mars (g = 3.69m/s2)
Mercury (g = 3.70m/s2)
1 2

Explanation / Answer

    we know that           Time period T = 2L / g                          L=   length of the pendulam                          g = acceleration due to gravity         frequency f = 1 / T                             = ( 1 / 2)g / L                        L = 8.17 m                         f = 0.1592 g / L         A)   For venus     g = 8.87m/s2                            f = 0.1592 8.87 / 8.17                                = 0.1658 Hz                For earth     g = 9.78m/s2                            f = 0.1592 9.78/ 8.17                                = 0.1741Hz               For moon     g =1.62m/s2                            f = 0.1592 1.62/ 8.17                                = 0.07 Hz              For mars    g = 3.69m/s2                            f = 0.1592 3.69/ 8.17                                = 0.1069Hz             For mercury   g = 3.70m/s2                            f = 0.1592 3.70/ 8.17                                = 0.1269 Hz so earth  have the greatestfrequency B )   Frequency is inversly proportional tolength              so if length high frequency is low           soA pendulum 2.99m will have smallest frequency                                 f = 0.1592 9.78/ 8.17                                = 0.1741Hz               For moon     g =1.62m/s2                            f = 0.1592 1.62/ 8.17                                = 0.07 Hz              For mars    g = 3.69m/s2                            f = 0.1592 3.69/ 8.17                                = 0.1069Hz             For mercury   g = 3.70m/s2                            f = 0.1592 3.70/ 8.17                                = 0.1269 Hz so earth  have the greatestfrequency B )   Frequency is inversly proportional tolength              so if length high frequency is low           soA pendulum 2.99m will have smallest frequency                                 f = 0.1592 1.62/ 8.17                                = 0.07 Hz              For mars    g = 3.69m/s2                            f = 0.1592 3.69/ 8.17                                = 0.1069Hz             For mercury   g = 3.70m/s2                            f = 0.1592 3.70/ 8.17                                = 0.1269 Hz so earth  have the greatestfrequency B )   Frequency is inversly proportional tolength              so if length high frequency is low           soA pendulum 2.99m will have smallest frequency                                 f = 0.1592 3.69/ 8.17                                = 0.1069Hz             For mercury   g = 3.70m/s2                            f = 0.1592 3.70/ 8.17                                = 0.1269 Hz so earth  have the greatestfrequency B )   Frequency is inversly proportional tolength              so if length high frequency is low           soA pendulum 2.99m will have smallest frequency                                 f = 0.1592 3.70/ 8.17                                = 0.1269 Hz so earth  have the greatestfrequency B )   Frequency is inversly proportional tolength              so if length high frequency is low           soA pendulum 2.99m will have smallest frequency     

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