Your friend is trapped in a castle tower. You want to send hera message by attac
ID: 1723060 • Letter: Y
Question
Your friend is trapped in a castle tower. You want to send hera message by attaching it to an arrow and shooting the arrow into awindow in the tower. The angle of the arrow when it leaves the bowis 40 degrees, measured from the horizontal, and its initialvelocity is 90 m/s. You are d = 80 m from the tower, and youcan neglect your height. How long does it take to the arrow to reach the window in thetower? And how high above the ground, h, is the window? Your friend is trapped in a castle tower. You want to send hera message by attaching it to an arrow and shooting the arrow into awindow in the tower. The angle of the arrow when it leaves the bowis 40 degrees, measured from the horizontal, and its initialvelocity is 90 m/s. You are d = 80 m from the tower, and youcan neglect your height. How long does it take to the arrow to reach the window in thetower? And how high above the ground, h, is the window?Explanation / Answer
This is a projectile motion problem. The horizontal distance is represented by the equation: x = Vox * t to find the initial velocity in the x direction (Vox) use theequation Vox = Vcos Vox= 90cos40= 68.944m/s Now we can find the time by plugging in the velocity into thedistance equation 80 = 68.944 * t t = 1.16 sec Now we can use the time to find the height using theequation: y = Voy*t + .5(-g)t^2 to find the velocity in the vertical direction use theequation: Voy = Vsin Voy = 90sin40= 57.8509m/s Now we can use the velocity and the time to find theheight: H= 57.8509(1.16) + .5(-9.8)(1.16)^2 H= 60.5136 m I hope this helps! I hope this helps!Related Questions
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