P h www.mathxl.com/Student/Playe 0079&questionld-5;&fAlushed-false;&cld-3784602;

Question

P h www.mathxl.com/Student/Playe 0079&questionld-5;&fAlushed-false;&cld-3784602;&centerwin; yes Fahad Homework: Homework 12-Normal Distribution/Margin of Error Ex. Score: 0 of 1 pt Score: 29.17% (3,5 of 12 pts) S of 12 complete Assume that a set of test scores is normally distributed with a mean of 80 and a standard deviation of 10. Use the 68-95-99.7 rule to find the following quantities The percentage of scores less than 80 is%. at The percentage ofscores less than 80 isDa Round to one decimal place as needed.)

Explanation / Answer

Answer :

Given that

Mean is 80 and a standard deviation of 10.

Since 80 is the mean, the fraction less than that is 50%. You don't need to invoke a 68-95-99.7 rule to figure that out. You also don't need to know the standard deviation.

Another way

The percentage of scores less than 80 is

(80-80)/10 = 0

Percent < 80 = Normal Percent < 0 = 50%

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.