Linear Algebra Matrices: Solve Problems 10 thru 13 A= [3 4 -1 2 1 0 3 1 2 5 -4 0
ID: 1719420 • Letter: L
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Linear Algebra Matrices: Solve Problems 10 thru 13
A= [3 4 -1 2 1 0 3 1 2 5 -4 0], B = [1 0 0 1 1 1 1 -1], C [1 2 3 -1 0 2 3 1] Does the matrix D = ABC exist? if so, d_34 = Does the matrix E = BAC exist? If so, e_22 = Does the matrix F = BCA exist? If so, f_43 =. Does the matrix G = ACB exist? If so, g_31 = A = [1/2 1/2 1/2 1/2]and B [1 0 0 -1], and C = AB. Evaluate the following matrices: Let A = [1 1/.3 c d] c d Find numbers c and d such that A^2 = 0. Supercom Ltd. produces two computer models PC1086 and PCI 186. The matrix A = [1.2 1.6 0.3 0.4 0.5 0.6] shows the cost per computer (in thousands dollars) for raw materials, labor and miscellaneous. And B = [3 8 6 9 6 2 4 3] the production figures for each quarter of the year 2010 (in multiples of 10000 units) . Find a matrix C that shows the shareholders the cost per quarter (in millions of dollars) for raw materials, labor and miscellaneous.Explanation / Answer
Per Post only one question
10) a) D=ABC exist and d34=2
b)c)d) matrix does not exist
11) A*A=A so A^37 =A hence A={(0.5,0.5),(0.5,0.5)} B={(1,0),(0,-1)} B*B={(1,0),(0,1)} and B^3=B so B^63=[B^3]^21=B
C=AB={(0.5,-0.5),(0.5,-0.5)} C*C=0 hence C^42=0
12) A*A={(1+c*1/3, 1/3+d*1/3),(c+cd, 1/3+d^2)} which give 1+c*1/3=0 which gives c=-3 and 1/3+d*1/3=0 gives d=-1
c=-3 and d=-1
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