The horizontal locations of the proximal and distal ends of a segment are shown

Question

The horizontal locations of the proximal and distal ends of a segment are shown for three time points (sampled at 60Hz) in the table below. The center of mass of the segment is located 43% of the segment length from the proximal end. What was the horizontal velocity of the segmental center of mass for frame 2? the table of info is below

D Question The horizontal locations of the proximal and distal ends of a segment is located 43% of the segment length from the pro Frame Proximal Distal 1 1.2261.238 2 1.587 597 1.597 1.978 1.907 D Question 7 A skatar is sliding forward (positive direction) on a fat rink at 6 m resistance is 16.4 N acting backward. These are the only horisont 0.5360

Explanation / Answer

Center of mass for frame 2   =   proximal end + 43 % * (distal end - proximal end)

                                         = 1.587 + 0.43 * (1.597 - 1.587 )

                                         = 1.5913

angular velocity = 2* pi * 60 = 377 rad/s

Horizontal Velocity = angular velocity * 1.5913

                             = 1.5913 * 377     units/s

                              = 599.9 units/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.