The lattice parameter for molybdenum is 0.31468-nm and its density at 20degreeC

Question

The lattice parameter for molybdenum is 0.31468-nm and its density at 20degreeC is 10.22-g/cm^3. Determine the crystal structure for molybdenum. Calculate the atomic packing factor(APF) for FCC-Fe iron (r_Fe = 1.269A). Also calculate the APF for FCC-Fe containing an interstitial carbon atom in the body-centered position, coordinates 1/2,1/2,1/2. Determine the Miller indices for the following the three crystal directions shown below. For the elements in atomic number from 22-30, which ones are allotropic. What are their allotropic transformations and at what temperatures?

Explanation / Answer

1)

        No . of atoms in lattice = 2 atoms / unit cell

       Therefore Molybdenum has BCC structure.

2) In the case of FCC structures, APF = 4. 4/3**r3 / a3. Since r = a*(2)^1/2 /4, evaluation of APF = 0.740.

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