Determine the maximum torque on a current loop having 20 turns, a cross-sectiona

Question

Determine the maximum torque on a current loop having 20 turns, a cross-sectional area of 0.1m^2, and experiencing a current of 20 mA. The magnetic held strength is 0.4 Wb/m62. 1 Wb/m^2 = 1 kg/(s^2 Ampere) Please use SI unit for torque to find the final answer Consider a Wheatstone bridge circuit that has all resistances equal to 100 Ohm One arm of the bridge is a sensor that cannot sustain a power dissipation of more than 0.25 W. What is the maximum value of E_i that can be employed for this bridge?

Explanation / Answer

Answer 1.

GIven N= 20 turns

I= 20 mA

A= 0.1 m2

B= 0.4 Wb/m2

for Max torque sin =1

Torque () = NIABsin = 20 x 20mA x 0.1 x 0.4 x1 => 0.016 Nm (Note: all values are in SI & answer)

Answer 2.

For the wheatstone bridge

If on arm of the bridge is sensor that cannot susbtain a power dissipation of more than 0.25 W. then V or Ei = PxR => 0.25 x 100 => 5 Volts

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