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ation by force tem Problem 4.3 previous 3 of 7 |next Problem 4.3 Part A The comp

ID: 1714067 • Letter: A

Question

ation by force tem Problem 4.3 previous 3 of 7 |next Problem 4.3 Part A The composite shaft, consisting of aluminum, copper and steel sections, is subjected to the loading shown. The cross-sectional areas of sections AB, BCand CD are AAB = 0.10 in2 , HC-0.15 n' , and ACL) = 0.04 in2 , respectively. The modulus of elasticity for each section are shown in the figure. Noglect the size of the collars at B and C (Figure 1) Determine the normal stress in section AB Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. TAD 22.2 ksi Submit My Answers Give Up Figure 1 Incorrect; Try Again; 5 attempts remaining Copper E-18(10) ksi Aluminum Steel E..-10(103) ksi E.-29(10) ksi Part B Determine the normal stress in section BC 3.50 kip 1.75 kip Express your answer to three significant figures and include the appropriate units. Enter negative value in the case of compression and positive value in the case of tension. 2.00 kip 1.50 kip 50 kip175 kip 12 i 18i 16i oc Value Units Submit My Answers Glve Up

Explanation / Answer

Part A:

Load in section AB = 2 kips (tension)

Area of cross section of AB = 0.1in2

Normal stress in AB = 2/0.1=20 ksi

part B:

Load in section BC = -3.5-3.5+2=-5 kips = 5 kips (compression)

Area of BC = 0.15in2

Normal stress in BC = -5/0.15=-33.33 ksi

Part C:

Load in section CD=-1.5kips = 1.5kips(compression)

area of CD=0.04in2

Normal Stress in CD = -1.5/0.04=-37.5 ksi

Part D:

Displacement of A with respect to D = -1.5*16/(0.04*29*103) - (5*12)/(0.15*18*103)+(2*18)/(0.1*10*103) = -0.007 in

A moves towards E and the displacement is 0.007in