Ice bags are delivered to a soft-drink kiosk and must be lifted from floor to ov

Question

Ice bags are delivered to a soft-drink kiosk and must be lifted from floor to overhead about 6 inches horizontally away from the body and 15 inches from the vertical centerline originating at the ankles. No turning of the body is required. Delivery of the ice bags occurs once or twice per shift, and the total amount of ice each time is about 360 lbs. All the ice should be put away within a minute or two after arriving. Slipperiness of the floor and awkwardness of the bag cause no difficult. Each bag weights 40-lb (ice bags are delivered to a beverage store and these should be lifted from the floor, about 6 inches horizontally and 15 inches vertically.) There are no turns in this task, bag deliveries occur one to two times per shift and The total amount of ice delivered is 360 lbs.All the ice must be moved in one or two minutes after it arrives. There is no effect on the task of the roughness of the floor and the difficulty of grabbing the bag. 40 lbs). What is the value of HM and VM in this problem? (What is the value of HM and VM in this problem?) O 0.90, 0.85 0.52, 0.67 0.94, 1 O 1,0.78

Explanation / Answer

HM = 1 and VM = .78

Actually HM is calculated by formula 10/H when the H value is above 10inch and if H value is less than then HM is 1.

To determine the vertical the absolute value or deviation of V from an optimum height of 30inch.when V is 30inch then VM is 1 and VM is decreases if V is inches or decreases linearly so for given problem V is 8inch so VM is .78.

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