1. A forward loop has a length of 1501.33 ft. measured in 12 setups. The allowab
ID: 1712168 • Letter: 1
Question
1. A forward loop has a length of 1501.33 ft. measured in 12 setups. The allowable mis-closure is 2. The turning point elevation is 8.11' and the back-sight is 0.55. What is the height of the instrument used for this leveling setup? 3. The fore sight for the leveling in question 2 was 1.85'. What is the elevation of turning point? 4. A forward loop has a length of 1777.3377 ft. measured in 9 setups. The allowable mis-closure is? For a second order, class one survey with a length of 5,280 feet, what is the allowable misclosure in mm? 5. A forward leg of a leveling loop has a length of 3501.33 ft. measured in 12 setups. The benchmark elevation is 123.45'. The elevation at the end of the forward leg was 155.55'. The backwards leg of the loop (12 set-ups) shows the bench marg to have an elevation of 123.89 6. i. The misclosure is: ii. The allowable misclosure is: If two cities are separated by 105 km, what is the curvature correction factor in kilometers for the distance between the cities if refraction is ignored? 7. 8. What would the correction for refraction be between the two cities that are separated by 19,300 meters? For a second order, class one survey with a length of 11,111 feet, what is the allowable misclosure in mm? 9. A forward loop has a length of 3333.33 ft. measured in 20 setups. The backward loop has a length of 3332.50 as measured in 20 set ups. (USE FOR QUESTIONS 10-11) 10. The misclosure is: 11 The allowable first order first class misclosure is:Explanation / Answer
prob.1
Allowable misclosure = 0.002*sqrt root.(loop length) = 0.002*sqrt.rt(1501.33) =0.0774 ft
prob.2
HI = BS+ Elevation of TP1 = 0.55'+8.11' = 8.66'
prob.3
Elevation of TP2 = HI - FS = 8.66-1.85' = 6.81'
prob.4
Allowable misclosure = 0.002*sqrt root.(loop length) = 0.002*sqrt.rt(1777.3377) = 0.0843 ft
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