A 5 kg bowling bowl (modeled as a sphere) with radius 0.22 m is resting on a 10

Question

A 5 kg bowling bowl (modeled as a sphere) with radius 0.22 m is resting on a 10 kg cart. The track that holds the bowling ball is bowed downwards with a height difference of 10 cm, from top-to-bottom. Ignore the mass of the cart wheels Ignoring friction, how fast would the cart be moving if the bowling ball rolls without slipping down to the bottom of the track (starting from rest at the top of the track)? If the coefficient of friction between the floor and the cart is Au 0.1, how fast would the cart be moving when the bowling ball rolls without slipping to the bottom of the track (starting from rest at the top of the track)?

Explanation / Answer

a)

equate potential energy in to = kainetic energy

1/2mv2 = mgh

1/2*5*V2 = 5*9.81*0.1

v= 1.4 m/sec

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