-A crate of mass m (=30 kg) is placed at rest on a (frictionless) inclined plane
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Question
-A crate of mass m (=30 kg) is placed at rest on a (frictionless) inclined plane, which has an angle (= 60o) above horizontal.
a)How long would it take the crate to slide 8 m down the incline?
b)If the crate were kept from sliding by a rope pulling parallel to the incline, what would the size of the tension be?
-While waiting at the airport for your flight to leave, you observe some of the jets as they take off. With your watch you find that it takes about 36.4 seconds for a plane to go from rest to takeoff speed. In addition, you estimate that the distance required is about 1.3 km.
(a) If the mass of a jet is 1.82 multiplied by 105 kg, what force is needed for takeoff?
-Two crewmen pull a boat through a lock, as shown in Figure 5-25. One crewman pulls with a force of F1 = 115 N at an angle of ? = 38° relative to the forward direction of the raft. The second crewman, on the opposite side of the lock, pulls at an angle of 45°. With what force F2 should the second crewman pull so that the net force of the two crewmen is in the forward direction?
Explanation / Answer
Crate mass = M = 30 kg Angle of inclination = = 60o distance to which object has to be slide = S = 8 m since , it starts from rest , intial velocity is = U = 0 m/s let , V be the velocity of the crate at 8 m by the known relation for acceleration a = g sin = ( 9.8 ) sin 60 = 8.48 m/s2 by the kinematic relation , V2 - U2 = 2aS V = 2 a S = 2 (8.48)(8) = 11.64 m/s (a) time = t = distance / velocity = 8 / 11.64 = 0.687 sec (b) by the free- body diagrom tension should be equal to T = mg sin = 30 * 9.8 * 0.866 = 254.604 N (appx.) plz. post B seperetely..,Related Questions
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