1) A thin gold ring of radius 1.02 cm carries a uniform charge per unit length o
ID: 1706187 • Letter: 1
Question
1) A thin gold ring of radius 1.02 cm carries a uniform charge per unit length of 1.03e-14 C/m. Find the electric field on the axis of the ring 1.10 cm from the center.2) The earth's surface charge density (-1.0 10-9 C/m2) is roughly balanced by a net positive charge in the lower 10 km of the earth's atmosphere. What is the average volume charge density of this atmospheric charge?
3) An electron is initially at rest just outside a large copper surface that has a charge density of 1.12 10-6 C/m2. How far has the electron moved in 1.03 10-9 s if the field is uniform over this region? (Enter the magnitude only.)
4) A long wire has a radius of 1.29 mm. If charges on the surface of the wire produce an electric field just outside its surface of 588 N/C, what is the magnitude of the electric field a distance of 2.58 mm from the wire's surface?
Explanation / Answer
1) A thin gold ring of radius 1.02 cm carries a uniform charge per unit length of 1.03e-14 C/m. Find the electric field on the axis of the ring 1.10 cm from the center. total Q=1.03e-14*1.02e-2*2pi=6.6e-16(C). E=kqh/(h^2+R^2)^3/2=0.019(V/m) 2) The earth's surface charge density (-1.0 10-9 C/m2) is roughly balanced by a net positive charge in the lower 10 km of the earth's atmosphere. What is the average volume charge density of this atmospheric charge? they equal other (the positive charged volume and the negative charged surface). so 1e-9*S=?*10e3*S. where ? be volume charge density. so ?=1e-13(C/m3) 3) An electron is initially at rest just outside a large copper surface that has a charge density of 1.12 10-6 C/m2. How far has the electron moved in 1.03 10-9 s if the field is uniform over this region? (Enter the magnitude only.) E=?/epsilon0=1.265e5(V/m). a=F/m=Eq/m=2.22e16(m/s2). s=at^2/2=0.0118(m)=1.18(cm) 4) A long wire has a radius of 1.29 mm. If charges on the surface of the wire produce an electric field just outside its surface of 588 N/C, what is the magnitude of the electric field a distance of 2.58 mm from the wire's surface? Gauss's law. 588*L*1.29e-3*2pi=E*L*2.58e-3*2pi so E=294(V/m)
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