In a football game, a player1 is running in the negative x direction at a speed

Question

In a football game, a player1 is running in the negative x direction at a speed of 6 yards per second. Player2 is running at a speed of 5 yards per second in the negative y direction, and intercepts the player1 at the 3 yard line, grabbing him tightly. The players' momentum carries them in a straight line. If player1 weighs 201 lbs, player2 weighs 171 lbs, and player2 meets player1 at a point 2 yards from the sideline (the x axis), what is the players' velocity after player2 grabs player1?
Answer in component form ( _i + _j) yd/s

Explanation / Answer

Use conservation of momentum, where m1v1 + m2v2 = m1v1' +m2v2' Since the final condition is both player mooving together, hence v1' = v2' = v' Input the value 201 lbs * -6yd/s i + 171 lbs *-5yd/s j = (201 lbs +171lbs) v' (-3.242i - 2.23j ) yd/s = v'

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