- 5.00 kg of some liquid at 10.0 oC is mixed with 1.00 kg of the same liquid at

Question

- 5.00 kg of some liquid at 10.0 oC is mixed with 1.00 kg of the same liquid at 40.0 oC. what is the final equilibrium temperature? ignore any heat flow with the containers and/or surroundings
a) 12.0 oC
b) 15.0 oC
c) 18.0 oC
d) 25.0 oC

-on which large surface should you place a hot pot if you want to cool off the pot as quickly as possible?
a) a smooth glass surface
b) a smooth steel surface
c) a rough steel surface
d)a smooth wood surface
e) a rough wood surface


- one mole of a diatomic gas has an initial temperaturebof 293 k. its internal energy is increased by 85.0 J. what is the final temperature of the diatomic gas?
a) 293 K
b) 294 K
c) 295 K
d) 296 K
e) 297 K


thanks a lot

Explanation / Answer

The mass m1 = 5.0kg and temperature T1 = 10C

the another mass m2 = 1.0kg and temperature T2 = 40C

from calorimetry

       m1cT1 = m2cT2

        m1( T - 10) = m2(40-T)

       5T - 50 = 40 - T

       6T = 90

then the final temperature T = 15 deg

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which large surface should you place a hot pot if you want to cool off the pot as quickly as possible

is depends upon the specific heat of the material so for rough steel have low specific heat then it can cools fast then the others therefore the choice is (c)

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The internal energy of the diatomic atom is

         Ein = nCv dT

          85J    = (1) (5/2R) (T - 293)

          85 = 2.5(8.31) (T - 293)

         T-293 = 4

therefore T = 297K

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