the moment of inertia of the pully system is I = 1.70 kg*m^2. the pulley consist

Question

the moment of inertia of the pully system is I = 1.70 kg*m^2. the pulley consists of two cylindrical spools firmly attached to each other. Radii of two cylindrical spools are r1 = 50cm and r2 = 20 cm respectively. a mass m1 = 2kg is attached by a light strong rope to the spool of radius r1 and mass m2 = 1.8 kg is attached by a light strong rope to the spool of radius r2. determine the angular acceleration of the pulley (your answer should be a magnitude with proper units) and tension forces T1 and T2 in two strings that hold masses m1 and m2.

Explanation / Answer

we have that. (m1gr1-m2gr2)=w*I+m1*w*r1^2+m2*w*r2^2. where w is the angular acceleration. so that w=2.76(rad/s2). ------- tension T1. m1g-T1=m1*w*r1. so T1=16.8(N). -------- T2 T2-m2g=m2*w*r2 so T2=18.6(N).

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