A boom (pole Out offers support) of length L and negligible mass is attached to

Question

A boom (pole Out offers support) of length L and negligible mass is attached to a pivot and can route. A 10 N block hangs from the midpoint of the boom. How many forces are acting on the boom? Remember, the boom has negligible mass. _______ On the diagram at right, draw and label the force acting on the boom. Let's call tension "FT" so we don't confuse it with the "T" of torque. Compute the tension in the cable. Which, if either, is stronger: Ty (vertical component of lent too) or W (weight of hanging block)? Then why doesn't the boom fell? Which statement below regarding the force on the boom from pivot P is true? The magnitude of the force is zero. The force has a nonzero horizontal component. The force has a nonzero vertical component. I only ( )II only ( ) III only ( ) I and II ( )II and III

Explanation / Answer

a) tension of string, pivot's force, weight of the hanging block. b)net torque about the pivot is zero. T*sin30*L=mg*L/2 so T=mg/2sin30=10(N). c)W is stronger. d) because there is vertical force come from the pivot , this force go upward. e)both II and III are correct.

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