<p>Enhanced College Physics 7 ed. Ch. 8 Problem #10. <br /><br />Here\'s the ful

Question

<p>Enhanced College Physics 7 ed. Ch. 8 Problem #10. <br /><br />Here's the full question, but I have a link for it to and the steps to solving it.<br /><br />10. A meterstick is found to balance at the 49.7cm mark when placed on a fulcrum. When a 50g mass is attached at the 10cm mark, the fulcrum must be moved to the 39.2cm mark for balance. What is the mass of the meterstick?<br /><br />I have the diagram figured out and all of the data, but I don't know where the equation they use comes from. I understand how to do the problem and find the answer with the equation, but I don't understand which equation is actually used. Please help!</p>

Explanation / Answer

its in equilibrium so net torque about the fulcrum is zero. so that you can have this equation. 50*(39.2-10)=M*(49.7-39.2) so M=139(g)

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