The gravitational force of attraction between two pebbles 60 cm apart is 4,32 ti
ID: 1700447 • Letter: T
Question
The gravitational force of attraction between two pebbles 60 cm apart is 4,32 times 10-13 N. If one pebble has three times the mass of the other pebble, find the mass of each pebble. Which is stronger: the gravitational force between the moon and the sun (Ms = 1.99times1030 kg) or the gravitational force between the moon and the Earth? The moon is 3.89times108 m from Earth and 1.49times1011 m from the Sun. Does the moon orbit the Earth or the sun? Check out the online gravity simulator at: http://phet, Colorado.edu/sims/my-solar-system_en.html. The link is on the website if you don't feel like typing this in. When you get to the website, select "Sun, planet, moon" on the upper right hand corner. Then press "start*. Is the moon orbitting the Earth or the Sun?Explanation / Answer
Gravitational force F = GmM / r ^ 2 Where G = gravitational constant = 6.67*10^-11 Nm^ 2/ kg^ 2 F = force = 4.32*10^-13 N r = separation = 60 cm = 0.6 m and M = 3m plug the values we get F = 3Gm^ 2 / r^ 2 from this m^ 2 = Fr^ 2 / 3G plug the values we get m^ 2 = 0.0777* 10^-2 m = 0.02787 kg (b). Gravitational force between moon and sun F = GM’M / R ^ 2 Where G = gravitational constant = 6.67*10^-11 Nm^ 2/ kg^ 2 M = mass of sun = 1.99*10^30 kg R = distanc eof he moon from sun = 1.49*10^11 m Plug the values we get F = 5.97 * 10^-3 * M ‘ Gravitational force between moon and earth F ‘ = GM’M” / R ^ 2 Where G = gravitational constant = 6.67*10^-11 Nm^ 2/ kg^ 2 M” = mass of earth = 5.98* 10^24 kg R = distanc eof he moon from earth = 3.89*10^8 m Plug the values we get F ‘ = 2.635*10^-3* M ‘ F > F ‘ So, force due to sun is stronger
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