A fireworks rocket is launched vertically (y-direction) into the night sky with

Question

A fireworks rocket is launched vertically (y-direction) into the night sky with an initial speed of 45.2 m/s. The rocket coasts after being launched, then explodes and breaks into two pieces of equal mass 2.40 s later.

(a) If each piece follows a trajectory that is initially at 45.3° to the vertical, what was their speed immediately after the explosion?
m/s

(b) What is the velocity of the rocket's center of mass before and after the explosion?
( m/s) y-direction

(c) What is the acceleration of the rocket's center of mass before and after the explosion?
( m/s2) y-direction

Explanation / Answer

a ) speed immediately after explosion is v = 45.2 m/s - 9.8 * 2.40 s

                                                                  = 21.6 m/s

                                                                  = 21.6 m/s / cos ( 45.3 )

                                                                  = 30.7 m/s

b ) velocity of rocket's center of mass before and after collission is

                           v = 21.6 m/s

c ) acceleration is   v = u + at

                              30.7 m/s   = 21.6 m/s + a * 2.40 s

      acceleration of center of mass for before and after collission is   a   = 3.79 m/s^2

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