One way to determine the inductance of an inductor is to place it in a series ci
ID: 1697466 • Letter: O
Question
One way to determine the inductance of an inductor is to place it in a series circuit with a resistor and capacitor of known values. The circuit is driven by a variable-frequency AC generator with a constant emf, and the frequency is varied until the current through the resistor, as measured by an AC ammeter, reaches a maximum. (a) A circuit like this is used with R = 235 O, C = 1.50×10-5 F, and maximum emf of 145 V. The current reaches a maximum when the frequency is 322 Hz. (a) What is the inductance? (b) What is the maximum current?A) _______H
B)________A
Explanation / Answer
Given
resistance of the resistor R = 235
capacitance of the capacitor C = 1.5*10^ -5 F
maximum emf = 145 V
Frequency f = 322 Hz
The current reaches at maximum the frequency is resonance frequency
f = 1 / [2(LC )^(1/2) ]
(LC )^(1/2) = 1 / 2f
= 1 / 2*3.14* 322
L =0.016 H
Maximu m current I = V / Z
where
impedance Z = (R^2 + (X L - XC )^2 ) ^ ( 1 /2 )
= ( 235 ^2 )^ (1 /2 )
I = V / 235 = 145 /235 = 0.617 A
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