A particle passes through a mass spectrometer as illustrated in the figure above

Question

A particle passes through a mass spectrometer as illustrated in the figure above. The electric field between the plates of the velocity selector has a magnitude of 7813 V/m, and the magnetic fields in both the velocity selector and the deflection chamber have magnitudes of 0.0906 T. In the deflection chamber the particle strikes a photographic plate 39.8 cm removed from its exit point after traveling in a semicirlce.

(a) What is the mass-to-charge ratio of the particle?________kg/C

(b) What is the mass of the particle if it is doubly ionized?________kg

(c) What is its identity, assuming it's an element?

Explanation / Answer

We know that. Bqv=F=mv^2/r so Bq=mv/r. so m/q=Br/v ------- Bqv=E*q. so Bv=E so v=E/B plug this in above equation. m/q=Br/(E/B)=B^2r/E=4.18e-7(kg/C) ---------- i dont get part b and c. are you sure that is the whole question

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