The expression describing the electric field vector of an electromagnetic wave i
ID: 1696770 • Letter: T
Question
The expression describing the electric field vector of an electromagnetic wave is: = 0.002 cos (omegat - 4piz) where the magnitude of the electric field is in volts/m, the time in seconds and the distances are in meters. (Points will be taken off for missing units in your answers.) Find the wavelength of these electromagnetic waves. Find the period and the frequency Determine the angular frequency omega. What is the direction of propagation and the direction of electrical oscillations for these electromagnetic waves? What is the amplitude of the magnetic field of these electromagnetic waves?Explanation / Answer
comparing given with the equation E = A cos(wt - kz)
(a) wave length = 2*pi / K = 2*pi / 4*pi = 0.5 m
(b)frequency = c / = 3*10^8 / 0.5 = 6*10^8 hz
time peroid = T = 1/ frequency = 1 / 6*10^8 =0.16*10^-8 sec
(c)angular frequency w = 2*pi *frequency = 6.28 *6*10^8 = 37.68*10^8 rad /sec
(d)the direction of propagation along the z - axis
the direction of elecrtic oscillations along y - axis
(e) magnitude of magnetic oscillations
B_o = E_0 / c = 0.002 / c = 0.002 / 3*10^8 = 6.66*10^-12 T
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