I NEED HELP WITH THE 2ND PART... 1st PART: Imagine John lives on the Earth. Mary
ID: 1695501 • Letter: I
Question
I NEED HELP WITH THE 2ND PART...1st PART: Imagine John lives on the Earth. Mary is traveling past the earth with a velocity of 8300m/s. If a meteor moving in the same direction passes Mary, and she measures the meteor's velocity to be 15700m/s.What is the magnitude of the velocity of the meteor as seen by John?
ANSWER: 2.40e4
2nd PART: Now assume that Mary's speed is 1.16×108m/s and the meteor's speed as it passes her is 2.40×108m/s. What is the magnitude of the velocity of the meteor that John sees now?
Explanation / Answer
In 2nd part velocities are comparable to velocity of light. So according to the relativistic addition of velocities [see the formula for relativistic addition of velocities] velocity of meteor as seen by john = [(1.16 + 2.40)/(1+ (1.16*2.40/9)) ] * 10^8 = (3.56/1.3093) * 10^8 = 2.719 *10 ^8
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