A rocket is launed at an of 54.0 degree above the horizontal with an intial spee

Question

A rocket is launed at an of 54.0 degree above the horizontal with an intial speed of 100m/s. The rocket moves for 3.00 s along its initial line of motion with an acceleration of 32.0m/s2 . At this time, its engines failsand the rocket proceeds to move as projectile. a) Find the maximum altitude reached by the rocket b) find its total time of flight c)find the horizontal range A rocket is launed at an of 54.0 degree above the horizontal with an intial speed of 100m/s. The rocket moves for 3.00 s along its initial line of motion with an acceleration of 32.0m/s2 . At this time, its engines failsand the rocket proceeds to move as projectile. a) Find the maximum altitude reached by the rocket b) find its total time of flight c)find the horizontal range

Explanation / Answer

   The angle of projection, theeta = 54 degrees    The initial velocity of projection, u = 100 m/s        (a)The maximum altitude reached, H = u2sin2theeta / 2g                                                       H = (100)2sin254 / 2(9.8)                                                       H = 333.9 m    (b)Time of flight, T = 2u sintheeta / g = 2(100)sin54 / 9.8 = 16.5 sec    (c)The horizontal range, R = u2sin2(theeta) / g                                       R = (100)2sin108 / 9.8 = 970.5 m        

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