The tub of a washer goes into it\'s spin cycle, starting from rest and gaining a

Question

The tub of a washer goes into it's spin cycle, starting from rest and gaining angular speed steadily for 8s,at which time it's turning at 5rev/s. At this point, the person doing the laundry opens the Lise, and a safety switch turns off the washer. The tub smoothly slows to rest in 12s. Through how many revolution does the tube turn while it is in motion?<br /><br />Would I find the angular acceleration and then apply that to get the final revelation then add the before and after revs together?

Explanation / Answer

Initial angular speed ? = 0 final angular speed  ? ' = 5.0 rev / s time t = 8.0 s Angu;ar accleration a = [ ? ' - ? ] / t                                 = ( 5.0 - 0 ) / 8.0 s                               = 0.625rev / s^ 2 No.of revolutions ? = [ ? ' ^ 2 - ? ^ 2 ] / 2a                               = ( 5.00 )^2 - 0 / 2 * 0.625                               = 20 rev (b)         initial speed ? ' = 5.0 rev /s       final angular speed ? " = 0        time t' = 8.0 s angular accleration a ' = [ ? " - ? ' ] / t '                                  = ( 0 - 5.00 ) / 12.0 s                                                     = - 0.41 rev /s^2 angular displacement ? = [ ? " ^ 2- ? ' ^ 2 ]/ 2 a'                                   = ( 0- 5.00 )^2 / 2 * - 0.41                                   = 30.4 rev                                   So, total revolutions = 20 +30.4                               = 50.4 rev Initial angular speed ? = 0 final angular speed  ? ' = 5.0 rev / s time t = 8.0 s Angu;ar accleration a = [ ? ' - ? ] / t                                 = ( 5.0 - 0 ) / 8.0 s                               = 0.625rev / s^ 2 No.of revolutions ? = [ ? ' ^ 2 - ? ^ 2 ] / 2a                               = ( 5.00 )^2 - 0 / 2 * 0.625                               = 20 rev (b)         initial speed ? ' = 5.0 rev /s       final angular speed ? " = 0        time t' = 8.0 s angular accleration a ' = [ ? " - ? ' ] / t '                                  = ( 0 - 5.00 ) / 12.0 s                                                     = - 0.41 rev /s^2 angular displacement ? = [ ? " ^ 2- ? ' ^ 2 ]/ 2 a'                                   = ( 0- 5.00 )^2 / 2 * - 0.41                                   = 30.4 rev                                   So, total revolutions = 20 +30.4                               = 50.4 rev Initial angular speed ? = 0 final angular speed  ? ' = 5.0 rev / s time t = 8.0 s Angu;ar accleration a = [ ? ' - ? ] / t                                 = ( 5.0 - 0 ) / 8.0 s                               = 0.625rev / s^ 2 No.of revolutions ? = [ ? ' ^ 2 - ? ^ 2 ] / 2a                               = ( 5.00 )^2 - 0 / 2 * 0.625                               = 20 rev (b)         initial speed ? ' = 5.0 rev /s       final angular speed ? " = 0        time t' = 8.0 s angular accleration a ' = [ ? " - ? ' ] / t '                                  = ( 0 - 5.00 ) / 12.0 s                                                     = - 0.41 rev /s^2 angular displacement ? = [ ? " ^ 2- ? ' ^ 2 ]/ 2 a'                                   = ( 0- 5.00 )^2 / 2 * - 0.41                                   = 30.4 rev                                   So, total revolutions = 20 +30.4                               = 50.4 rev

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