I was able to solve the first portion of the problem, but now I am stuck on part

Question

I was able to solve the first portion of the problem, but now I am stuck on part 2.

Here is the first part of the problem: In a nuclear research laboratory, a proton moves in a particle accelerator through a magnetic field of intensity 0.297 T at a speed of 4.02 × 10^7 m/s.
The charge on a proton is 1.60218 × 10^-19 C.
If the proton is moving perpendicular to the field, what force acts on it?
Answer in units of N. Correct answer: 1.91e-12 N
Here's the part I am stuck on: If the proton of mass 1.67262 × 10^-27 kg continues to move in a direction that is consistently perpendicular to the field, what is the radius of curvature of its path?.
Answer in units of m. Thanks!

Here is the first part of the problem: Answer in units of N. Correct answer: 1.91e-12 N
Here's the part I am stuck on: Answer in units of m. Thanks!

Explanation / Answer

a) F = B q v = 0.297 * 1.6 x 10^-19 * 4.02 x 10^7 = 1.91 x 10^-12 N b) r = m v / q B = 1.67262 × 10^-27 * 4.02 x 10^7 / 1.6 x 10^-19 * 0.297 = 1.4149 m

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