A one-dimensional impulse force acts on a 3.0 kg object as diagrammed in the fig

Question

A one-dimensional impulse force acts on a 3.0 kg object as diagrammed in the figure below. (a) What is the magnitude of the impulse given to the object?

(b) What is the magnitude of the average force?

(c) What is the final speed if the object had an initial speed of 6.0 m/s in a direction opposite to the impulse force?

(a) What is the magnitude of the impulse given to the object?

(b) What is the magnitude of the average force?

(c) What is the final speed if the object had an initial speed of 6.0 m/s in a direction opposite to the impulse force?

Explanation / Answer

(a) The area under the above curve gives the impulse. So area under the given curve = (1/2)(900N)(0.05s) + (900N)(0.09s - 0.05s) + (1/2)(0N - 900N)(1.4s - 0.09s) (b) The average force is 900 N. (c) From the work-energy theorem we have W = (1/2)mv^2 - (1/2)mu^2 Here W is substituted here which we got from part (a) m = 3.0 kg u = 6.0 m/s Solve for the value of final speed (v) of the object

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