Three very large square planes of charge are arranged as shown (on edge) in Fig.
ID: 1693642 • Letter: T
Question
Three very large square planes of charge are arranged as shown (on edge) in Fig. 21-70. From left to right, the planes have charge densities per unit area of -0.50 µC/m2, +0.15 µC/m2, and -0.20 µC/m2. Find the total electric field (direction and magnitude) at the points A, B, C, and D. Assume the plates are much larger than the distance AD. point D & direction Please explain !Three very large square planes of charge are arranged as shown (on edge) in Fig. 21-70. From left to right, the planes have charge densities per unit area of -0.50 MuC/m^2, +0.15 MuC/m2, and -0.20 MuC/m^2. Find the total electric field (direction and magnitude) at the points A, B, C, and D. Assume the plates are much larger than the distance AD. point A & direction point B & direction point C & direction point D & direction Please explain !
Explanation / Answer
The question specifies as left to right but i think it should be from top to bottom. The magnitude of the electric field is E1 = s1 / 2 eo = (0.5x10^-6) / 2 (8.85x10^-12) = 2.82x10^4 N/C E2 = s2 / 2 eo = (0.15x10^-6) / 2 (8.85x10^-12) = 8.47x10^3 N/C E3 = s3 / 2 eo = (0.2x10^-6) / 2 (8.85x10^-12) = 1.1299x10^4 N/C Net field and direction at point A is E = E1 -E2 +E3 = 2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = 3.1029x10^4 N/C to the right Net field and direction at point B is E = -E1 -E2 +E3 = -2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = - 2.533 x10^4 N/C to the left Net field and direction at point C is E = -E1 +E2 +E3 = - 2.82x10^4 N/C + 8.47x10^3 N/C +1.1299x10^4 N/C = -8.43x10^3 N/C to the left Net field and direction at point D is E = - E1 +E2 -E3 =- 2.82x10^4 N/C + 8.47x10^3 N/C -1.1299x10^4 N/C = - 3.1029x10^4 N/C to the left = (0.5x10^-6) / 2 (8.85x10^-12) = 2.82x10^4 N/C E2 = s2 / 2 eo = (0.15x10^-6) / 2 (8.85x10^-12) = 8.47x10^3 N/C E3 = s3 / 2 eo = (0.2x10^-6) / 2 (8.85x10^-12) = 1.1299x10^4 N/C Net field and direction at point A is E = E1 -E2 +E3 = 2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = 3.1029x10^4 N/C to the right Net field and direction at point B is E = -E1 -E2 +E3 = -2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = - 2.533 x10^4 N/C to the left Net field and direction at point C is E = -E1 +E2 +E3 = - 2.82x10^4 N/C + 8.47x10^3 N/C +1.1299x10^4 N/C = -8.43x10^3 N/C to the left Net field and direction at point D is E = - E1 +E2 -E3 =- 2.82x10^4 N/C + 8.47x10^3 N/C -1.1299x10^4 N/C = - 3.1029x10^4 N/C to the left = (0.15x10^-6) / 2 (8.85x10^-12) = 8.47x10^3 N/C E3 = s3 / 2 eo = (0.2x10^-6) / 2 (8.85x10^-12) = 1.1299x10^4 N/C Net field and direction at point A is E = E1 -E2 +E3 = 2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = 3.1029x10^4 N/C to the right Net field and direction at point B is E = -E1 -E2 +E3 = -2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = - 2.533 x10^4 N/C to the left Net field and direction at point C is E = -E1 +E2 +E3 = - 2.82x10^4 N/C + 8.47x10^3 N/C +1.1299x10^4 N/C = -8.43x10^3 N/C to the left Net field and direction at point D is E = - E1 +E2 -E3 =- 2.82x10^4 N/C + 8.47x10^3 N/C -1.1299x10^4 N/C = - 3.1029x10^4 N/C to the left = (0.2x10^-6) / 2 (8.85x10^-12) = 1.1299x10^4 N/C Net field and direction at point A is E = E1 -E2 +E3 = 2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = 3.1029x10^4 N/C to the right Net field and direction at point B is E = -E1 -E2 +E3 = -2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = - 2.533 x10^4 N/C to the left Net field and direction at point C is E = -E1 +E2 +E3 = - 2.82x10^4 N/C + 8.47x10^3 N/C +1.1299x10^4 N/C = -8.43x10^3 N/C to the left Net field and direction at point D is E = - E1 +E2 -E3 =- 2.82x10^4 N/C + 8.47x10^3 N/C -1.1299x10^4 N/C = - 3.1029x10^4 N/C to the left E = -E1 -E2 +E3 = -2.82x10^4 N/C - 8.47x10^3 N/C +1.1299x10^4 N/C = - 2.533 x10^4 N/C to the left Net field and direction at point C is E = -E1 +E2 +E3 = - 2.82x10^4 N/C + 8.47x10^3 N/C +1.1299x10^4 N/C = -8.43x10^3 N/C to the left Net field and direction at point D is E = - E1 +E2 -E3 =- 2.82x10^4 N/C + 8.47x10^3 N/C -1.1299x10^4 N/C = - 3.1029x10^4 N/C to the left E = -E1 +E2 +E3 = - 2.82x10^4 N/C + 8.47x10^3 N/C +1.1299x10^4 N/C = -8.43x10^3 N/C to the left Net field and direction at point D is E = - E1 +E2 -E3 =- 2.82x10^4 N/C + 8.47x10^3 N/C -1.1299x10^4 N/C = - 3.1029x10^4 N/C to the left E = - E1 +E2 -E3 =- 2.82x10^4 N/C + 8.47x10^3 N/C -1.1299x10^4 N/C = - 3.1029x10^4 N/C to the leftRelated Questions
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