I am doing a lab for Physics and it involves a wooden block that is tied to a st
ID: 1693351 • Letter: I
Question
I am doing a lab for Physics and it involves a wooden block that is tied to a string that is connected to a pulley with a mass hanging at the other end. How does the force acting on mass1 compare to the weight of mass 2. Mass 1's is 128g and mass 2 is 79g. This is also a large surface are of wood. We did a small surface area with wood and felt and also. As we increase the grams of M1, how does the force now compare to the weight of M2?Part 2 involves kinetic friction where we had the block moving at a constant velocity and added weight to it. How does the force of M1 compare to the wieght of M2? Im very lost and could really use some help, some basic knowledge put in very simple terms would be awesome. Thanks so much for your time. Danielle
Part I
Large Surface Wood Small Surface Wood
M1 (g) m2 (g) M1 (g) m2 (g)
128 79 178 55
178 115 228 73
228 143 248 75
248 162 328 78
278 175 378 116
Large Surface Felt Small Surface Felt
M1 (g) m2 (g) M1 (g) m2 (g)
228 57 228 50
248 61 278 57
278 68 298 65
298 72 328 71
328 79 348 76
Part II
Large Surface Wood Large Surface Felt
M1 (g) m2 (g) M1 (g) m2 (g)
130 79 178 50
150 95 198 55
180 120 228 61
198 130 249 65
228 145 280 75
Explanation / Answer
Given Mass of wooden block, M1 = 128 g , Mass hanging on other side, m2 = 79 g A)The net force acting on M1 is M1a = FT-------(1) Force acting on m2 is m2a = m2g - FT m2a = m2g - M1a a = m2 g /(M1 +m2) = 0.079 kg *9.8 m/s^2/(0.128 kg+0.079 kg) a = 3.74 m/s^2 now,FT = M1a = 0.128 kg *3.74 m/s^2 FT = 0.47 N Hence, the force on M1 = 0.47 N The force on m2 is m2g = FT =0.47 N both are equal --------------------------------------------------------------------------------- If we increase M1 = 178 g then a = 3.01 m/s^2 the force on M1 is FT =M1a = 0.178 kg *3.01 m /s^2 = 0.53 N weight of m2 is FT = 0.53 N ------------------------------------------------------------------------------------- B)If kinetic friction is there , then the net force is F = FT -Related Questions
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