1) A 0.30 kg ball is thrown straight up into the air with an initial speed of 13

Question

1) A 0.30 kg ball is thrown straight up into the air with an initial speed of 13 m/s. Find the momentum of the ball at the following locations.
a)What is the max height in kg*m/s
b)What is the halfway to the max height in kg*m/s

2) A 0.500 kg football is thrown toward the east with a speed of 20.0 m/s. A stationary receiver catches the ball and brings it to rest in 0.020 s. (Take the initial direction of motion to be the positive direction.)
a)What is the impulse delivered to the ball as it's caught? (in kg*m/s)
b)What is the average force exerted on the receiver? (in N)


****Please include a detailed explanation to these

Explanation / Answer

1) A 0.30 kg ball is thrown straight up into the air with an initial speed of 13 m/s. Find the momentum of the ball at the following locations.
a)What is the max height in kg*m/s
at the maximum height as the ball thrown vertically up the velocity =0
so the momentum=mass*velocity=0 kgm/sec
b)What is the halfway to the max height in kg*m/s
we know that maximum height=13*13/2*9.8=8.62m at the mid point the velocity=vu*u-2*g*h/2=9.19m/sec so momentum=9.19*0.30=2.758kgm/sec
2) A 0.500 kg football is thrown toward the east with a speed of 20.0 m/s. A stationary receiver catches the ball and brings it to rest in 0.020 s. (Take the initial direction of motion to be the positive direction.)
a)What is the impulse delivered to the ball as it's caught? (in kg*m/s)
impulse=change in momentum/time=[0- 0.500*20]/0.020=-500kgm/sec
b)What is the average force exerted on the receiver? (in N)
the average force exerted on the receiver= [change in momentum/time] of the ball=500kgm/sec


[change in momentum/time] of the ball=500kgm/sec

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