A person puhes on a stationary 125 N box with 75 N at 30 degrees below the horiz

Question

A person puhes on a stationary 125 N box with 75 N at 30 degrees below the horizontal. The coefficient of static friction between the box and the horizontal floor is .80 What is the normal force on the box? n=? What is the friction force on the box? F=? The person now replaces his push with 75 N pull at 30 degrees above the horizontal. Find the normal force on the box in this case. A person puhes on a stationary 125 N box with 75 N at 30 degrees below the horizontal. The coefficient of static friction between the box and the horizontal floor is .80 What is the normal force on the box? n=? What is the friction force on the box? F=? The person now replaces his push with 75 N pull at 30 degrees above the horizontal. Find the normal force on the box in this case.

Explanation / Answer

Weight of the box W = 125 N Force F = 75 N Angle with Horizontal ? = 30 degrees Coefficient of static friction µ = 0.80 (a) Normal force N = mg + F sin30                        = 125 + 37.5 = 162.5 N (b) Frictional force f = µN = 0.8*162.5 = 130 N (c) In this case Normal reaction N = mg - F sin30 = 125 - 37.5 = 87.5 N

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