you take a homemade accelerometer to an amusement park. this accelerometer consi
ID: 1692512 • Letter: Y
Question
you take a homemade accelerometer to an amusement park. this accelerometer consists of a metal nut attached to a string and connected to a protractor. while ridng a rollercoaster that is moving at a uniform speed around a circular path, you hold up the accelerometer and notice that the string is making an angle of 55 degrees with respect to the vertical with the nut pointing away from the center off the circle.what is the radial acceleration of the roller coaster in m/s and what is your radial acceleration expressed as a multple of g?
Explanation / Answer
? means the theta signT = means the SUM sign
(A).
look at free body diagram of metal nut, let T is string tension.
V = 0
T cos ? = m g ...............(1)
SH = m a
T sin ? = m a......................(2)
eqn (2) divided by eqn (1)
a/g = tan ?
a = g tan ? = 9.81 tan 55° = 14.01 m/s²
(B).
a = g tan ? = a = g tan 55° = 1.428 g
(C).
a = v²/R = g tan ?
v²/80 = (9.81) tan 55°
v = 33.48 m/s good luck
(A).
look at free body diagram of metal nut, let T is string tension.
V = 0
T cos ? = m g ...............(1)
SH = m a
T sin ? = m a......................(2)
eqn (2) divided by eqn (1)
a/g = tan ?
a = g tan ? = 9.81 tan 55° = 14.01 m/s²
(B).
a = g tan ? = a = g tan 55° = 1.428 g
(C).
a = v²/R = g tan ?
v²/80 = (9.81) tan 55°
v = 33.48 m/s good luck
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