consider 2 parallel metallic plates seperated by a distance of 5mm.. each plate
ID: 1692261 • Letter: C
Question
consider 2 parallel metallic plates seperated by a distance of 5mm.. each plate has an areas of 20 square meters, and one has a total positive charge of 5 uC and the other a charge of -5uCdraw a diagram illustrating
a) use gauss law to calculate the electric field between the two plates
b) use the value of E you just obtained to calcuate the potential difference between the two plates
c) calculate the speed of a 10gm particle of a charge +2uC if it is released from the positive plate as it arrives at the negative plate
show all equations used and work
Explanation / Answer
consider 2 parallel metallic plates seperated by a distance of 5mm.. each plate has an areas of 20 square meters, and one has a total positive charge of 5 uC and the other a charge of -5uCdraw a diagram illustrating
as cramster is not supporting please try to draw the diagram
a) use gauss law to calculate the electric field between the two plates
E=q/Ae0 where Q=5*10-6 A=20sqm e0=8.85*10-12 calculating we will get the value of E b) use the value of E you just obtained to calcuate the potential difference between the two plates
potential difference =E*distance between the plates =E*5*10-3
c) calculate the speed of a 10gm particle of a charge +2uC if it is released from the positive plate as it arrives at the negative plate
force on the 2*10-6charged particle=E*q=E*2*10-6 N
acceleration of the particle=Force/mass=F/10*10-3 now speed= v0+2*F/10*10-3*5*10-3
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