A student bikes to school by traveling first d_N = 1.10 miles north, then d_W =

Question

A student bikes to school by traveling first d_N = 1.10 miles north, then d_W = 0.500 miles west, and finally d_S = 0.200 miles south.

You will now find the same quantity algebraically, without the need to use much geometry. Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking.
Let d_vec_N be the displacement vector corresponding to the first leg of the student's trip. Express d_vec_N in component form.
Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, the x component is written first.

Explanation / Answer

The distance travelled in north direction d_N = 1.1 mile along +Y direction The distance travelled in west direction d_W = 0.5 mile along -X direction The distance travelled in south direction d_S = 0.2 mile along -Y direction The net displacement of the student alon X direction is -0.5 miles The net displacement of the student alon Y direction is 1.1-0.2 = 0.9 miles The net displacement of the student d_vec_N = (-0.5,0.9)

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