I need help figuring out this practice problem. Please provide a complete detail

Question

I need help figuring out this practice problem. Please provide a complete detailed explanation. Thanks.

Electron is at rest in a space with electric field with magnitude 700 N/C.

a) How long will it take for the electron to reach speed v = 1.2e5 m/s?
ans: 97.5 ns b) What is the distance between the initial position of the electron when it is at rest, and the position when it has reached a speed v = 1.2e5 m/s? ans 0.585 ans: 97.5 ns b) What is the distance between the initial position of the electron when it is at rest, and the position when it has reached a speed v = 1.2e5 m/s? ans 0.585

Explanation / Answer

initial speed u = 0 Electric field E = 700 N/C. final speed v = 1.2*10^5 m/s charge of electron q = 1.6 * 10^-19 C mass of electron m = 9.11810^-31 kg accleration a = Eq / m = 1.229*10^14 m / s^ 2 required time t = (v - u) / a = 9.75 * 10^-10 s = 97.5 ns b) the distance between the initial position of the electron when it is at rest, and the position when it has reached a speed v = 1.2e5 m/s is S = [v^ 2-u^ 2] / 2a S = 0.585 * 10^-6 m = 0.585 µm

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