A student tries to raise a chain consisting of three identical links. Each link

Question

A student tries to raise a chain consisting of three identical links. Each link has a mass of 330 kg. The three-piece chain is connected to a string and then suspended vertically, with the student holding the upper end of the string and pulling upward. Because of the student's pull, an upward force of 16 N is applied to the chain by the string. Use Newton's laws to answer the following questions. 1. Find the acceleration of the chain. 2. Find the force exerted by the top link on the middle link.

Explanation / Answer

Pulling force, F = 13 N ( vertically up ) Mass of each link, m = 0.210 kg Let a = Acceleration of the system T = force exerted by the top link on the middle (a) Net force, Fnet = F - (3m)*g                         = 13 - (3 * 0.210 * 9.8 )                         = 13 - 6.174                         = 6.826 N Acceleration, a = Net force / Total mass                         = 6.826 / (3 * 0.210)                         = 10.83 m/s^2 (b) Top and milddle links: F - T = m a T = F - ma    = 13 - (0.210 * 10.83)    = 10.73 N

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.