a)Find the expression for the power collected from an isotropic source with an i
ID: 1687948 • Letter: A
Question
a)Find the expression for the power collected from an isotropic source with an intensity equal to (Initial intensity)(W/sr) with a half angle aperture equal to alpha b) Repeat this for a lambertian source with intensity equal to (Initial intensity)cos(phi)(W/sr) a)Find the expression for the power collected from an isotropic source with an intensity equal to (Initial intensity)(W/sr) with a half angle aperture equal to alpha b) Repeat this for a lambertian source with intensity equal to (Initial intensity)cos(phi)(W/sr)Explanation / Answer
power collected from the isotropic source = P = intensity * area area of half angle aperture = pr^2 + p r s where s = slant height = ( r^2 + h^2 ) ^ ( 1 /2 ) h = height b) The emitted light from the die itself (without any optics) is usually very close to a Lambertian emission.A Lambertian emission refers to a source emitting the same quantity of light in all directions power emitted by a Lambertian source within a given cone: P = P_o sin ^2 (p) intensity of a die for small angle cones, normal to the surface:I ( ?=0)˜ P / O = P_o sin ^2 (p) / 2p ( 1 - cos? ) = (P_o / 2p )( ?^ 2 / ( 1-(1- ?^ 2 / 2 )) = P _o / p power emitted by a Lambertian source P = I p sin ^2 ( p ) where I = intensity
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