2 Cars face each other 100m apart, both cars start accelerating and begin moving

Question

2 Cars face each other 100m apart, both cars start accelerating and begin moving at the same time (t=0). Car A accelerates at 0.8 m/s2; Car B accelerates at 1.4m/s2. A.) Using the same coordinate system for each car, write expressions that describe the position of each car as a function of time. How would one go about finding the the functions for the two cars, A & B? 2 Cars face each other 100m apart, both cars start accelerating and begin moving at the same time (t=0). Car A accelerates at 0.8 m/s2; Car B accelerates at 1.4m/s2. A.) Using the same coordinate system for each car, write expressions that describe the position of each car as a function of time. How would one go about finding the the functions for the two cars, A & B?

Explanation / Answer

aA = 0.8 m/s^2, aB = 1.4m/s^2. choose car A' s starting position as x = 0, A goes in +x direction, then car B's starting position is 100 m, it goes in -x direction at time t A's position is xA = aA*t^2/2 = 0.4*t^2 B's position is xB = 100 - aB*t^2/2 = 100 - 0.7*t^2

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