A circular loop of wire of cross-sectional area 0.12 m^2 consists of 200 turns,

Question

A circular loop of wire of cross-sectional area 0.12 m^2 consists of 200 turns, each carrying 0.50 A. It is placed in a magnetic field of 0.050 T oriented at 30 degrees to the plane of the loop. What torque acts on the loop? The answer I am looking for is 0.52 m N
A circular loop of wire of cross-sectional area 0.12 m^2 consists of 200 turns, each carrying 0.50 A. It is placed in a magnetic field of 0.050 T oriented at 30 degrees to the plane of the loop. What torque acts on the loop? The answer I am looking for is 0.52 m N

Explanation / Answer

T=m*b T=200*0.12*0.5*0.05cos(30)=0.52 N.m

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