An antelope moving with constant acceleration covers the distance between two po

Question

An antelope moving with constant acceleration covers the distance between two points 68.0 m apart in 6.60 s. Its speed as it passes the second point is 14.0 m/s.

What is its speed at the first point?

What is its acceleration?
(Pleae give details on how to work the problem. The main thing I am unsure about is the initial velocity) Thanks!


An antelope moving with constant acceleration covers the distance between two points 68.0 m apart in 6.60 s. Its speed as it passes the second point is 14.0 m/s.

What is its speed at the first point?

What is its acceleration?
(Pleae give details on how to work the problem. The main thing I am unsure about is the initial velocity) Thanks!

Explanation / Answer

distance S= 68 m time t= 6.6 s speed at second point v = 14 m / s we know S = vt -( 1/ 2) at^ 2 68 = 92.4 - 21.78 a from this accleration a = 1.12 m / s^ 2 let the speed at first point be u then fromthe relation v= u+ at u = v - at = 6.606 m / s

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