A 1.4 kg ball is thrown upwards off the side of a cliff with a speed of 5.8 m/s

Question

A 1.4 kg ball is thrown upwards off the side of a cliff with a speed of 5.8 m/s and falls into the ocean 16 meters below. Once the ball hits the water it travels a depth of 1.4 m then floats to the surface. Assumingthat the acceleration of the ball hwne it is in the water remains constant, calculate the total time it takes from teh time the ball is thrown to the time it "pops" out of the water. What is the average force the water exerts on the ball while it is sinking?

Explanation / Answer

downward velocity when it reaches the level of side of cliff u = 5.8m/s now v2 - u2 = 2as =>v2 = 5.8^2 + 2*9.8*16 = 347.24 => v = 18.63m/s when in water initial velocity u = 18.63m/s final velocity =0 s = 1.4m => v2 - u2 = 2as => 0 - 18.63^2 = 2a*1.4 =>a = -124m/s2 average force = mass*acceleration = 124*1.4 = 173.6N

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