two hockey players, initially at rest, shove each other. The friction between th

Question

two hockey players, initially at rest, shove each other. The friction between their skates and the ice is negligible. After the shove, the first player travels at V1=0.82 m/s and the second player travels in the opposite direction at V2=0.74 m/s. a) what is the total linear momentum of the two players? b) what is the ratio of the mass of the first player to that of the second player? two hockey players, initially at rest, shove each other. The friction between their skates and the ice is negligible. After the shove, the first player travels at V1=0.82 m/s and the second player travels in the opposite direction at V2=0.74 m/s. a) what is the total linear momentum of the two players? b) what is the ratio of the mass of the first player to that of the second player?

Explanation / Answer

since the friction is negligible linear momentum is conserved since both are initially at rest their initial momentum taken together is 0 so by conservation of linear momentum final momentum taken together=0...(a) since final momentum is zero(taken together) m1v1+m2v2=0 m1v1=-m2v2 taking only magnitudes: m1v1=m2v2 m1/m2=v2/v1=0.9024......(b)

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