<DIV><IMG alt=\"\" src=\"https://s3.amazonaws.com/answer-board-image/41c7a3d2-53

Question

<DIV><IMG alt="" src="https://s3.amazonaws.com/answer-board-image/41c7a3d2-5338-41fb-b76f-922a1b96608c.gif" src_cetemp="https://s3.amazonaws.com/answer-board-image/41c7a3d2-5338-41fb-b76f-922a1b96608c.gif"><BR>A uniform plank of length 2.00 m and mass 25.0 kg is supported by three ropes, as indicated by the blue vectors in the figure below. Find the tension in each rope when a 710 N person is 0.500 m from the left end. magnitude of 1 1 N <BR>magnitude of 2 2 N <BR>magnitude of 3 3 N <BR><BR><BR><BR></DIV>

Explanation / Answer

St = -(710 N)(.500 m)-(25 kg)(9.8 m/s2)(1.00 m)+(T1sin40)(2.00 m) = 0 T1 = 466.7 N Then SFx = 0 gives -T3 + T1cos40 = 0 T3 = T1cos40 = 466.7cos40 = 357.5 N SFy = 0 gives T2 - (710 N + 25*9.8 N) + T1sin40 = 0 T2 = 955 N - 466.7sin40 = 655.0 N

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